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If a particle moves on a circular path of radius 4 m with time period 4 s, then the change in magnitude of velocity in one- fourth revolution will beA. `2sqrt2 pi m//s`B. `pi m//s`C. `3 pi m//s`D. `4 pi m//s` |
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Answer» Correct Answer - A `Deltav=2v "sin" (theta)/(2)` `v=r omega =4 xx (2pi)/(4)=2pi` |
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