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If a particle of charge 1μC is projected into a magnetic field vecB = (2hati + yhatj- zhatk) T with a velocity vecV = (4hati+2hatj - 6hatk)ms^(-1), then it passes undeviated. If it is now projected with a velocity vecV = hati + hatj , then find the force experienced by it? |
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Answer» Solution :Charged particle moves in a MAGNETIC field undeviated when `hatV` is parallel or anti parallel to `hatB` `(V_(k))/(B_(X))=(V_(y))/(B_(y))=(V_(z))/(B_(z))=k,4/2=2/y=(-6)/(-z)` y=1 z=3 `thereforevecB=(2hati+hatj-3hatk)` `vecF=q(vecVxxvecB)` `vecF=10^(-6)abs({:(HATI,hatj,HATK),(1,1,0),(2,1,-3):})` `vecF=10^(-6)[i(-3)-hatj(-3)+hatk(-1)]` `vecF=10^(-6)abs((-3hati+3hatj-hatk))N=sqrt(19)muN` |
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