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If a person goes to a height equal to radius of earth from its surface, what would be his weight relative to that on the earth? |
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Answer» At the surface of earth, weight w = mg = \(\frac{GMm}{R^2}\) At height, h = R, weight, w ′ = mg′ = \(\frac{GMm}{(R+h)^2}=\frac{GMm}{(R+R)^2}\) \(\therefore\) \(\frac{w'}{w}=\frac{R^2}{(2R)^2}\) = \(\frac{1}{4}\) or w' = \(\frac{w}{4}\) It means the weight would reduce to one-fourth of the weight on the surface of earth. |
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