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if a point p (x , y) is equidistant from the points A (-1,2 ) and B(2,-1) , find the relation between x and y. |
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Answer» <P>Answer: x-y =3 is the answer. Step-by-step explanation: Let the points be P(x,y), A(6,-1) and B(2,3). AP2 = (x-6)2 + (y+1)2 BP2 = (x-2)2 + (y-3)2 Given, 9(x,y) is equidistant from (6,-1) and (2,3) (x-6)2 + (y+1)2 = (x-2)2 + (y-3)2 x2 - 12x + 36 + y2 + 2y + 1 = x2 - 4x + 4 + y2 - 6Y + 9 -12x + 36 + 2y + 1 = - 4x + 4 - 6y + 9 -8x + 8Y = -24 -x + y = -3 x - y = 3. |
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