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If a semiconductor has an intrinsic carrier concentration of `1.41 xx 10^(16)//m^(3)` when doped with `10^(21)//m^(3)` at room temperature will beA. `2 xx 10^(21)`B. `2 xx 10^(11)`C. `1.41 xx 10^(10)`D. `1.41 xx 10^(16)` |
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Answer» Correct Answer - D Doping wil increasse the number of electrons only nad not the holes. So, number of holes will be equal to number of intrinsic carrier concentration. `=1.41 xx 10^(16)//m^(3)` |
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