1.

If a simple harmonic motion is represented by (d^(2)X)/(dt^(2))+alphax=0 its time period is :

Answer»

`2PI//alpha`
`2pi//sqrt(alpha)`
`2pialpha`
`2pi sqrt(alpha)`

Solution :`(d^(2)X)/(DT^(2))+alphax=0`
Comparing it with STANDARD equation of SHM.
`(d^(2)X)/(dt^(2))+W^(2)X=0` we have `w^(2)=a`
Time period `T=(2pi)/(w)=(2pi)/(sqrt(a))`
So the CORRECT choice is (b).


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