1.

If a simple harmonic motion is represented by `(d^(2)x)/(dt^(2)) + alphax = 0`, its time period is :A. `(2pi)/(alpha)`B. `(2pi)/(sqrt(alpha))`C. `2pialpha`D. `2pisqrt(alpha)`

Answer» Correct Answer - B
`(d^(2)x)/(dt^(2)) = -alphax………(i)`
We know `a = (d^(2)x)/(dt^(2)) = -omega^(2)x …….(ii)`
From Eq. `(i)` and `(ii)`, we have
`omega^(2) = alpha`
`omega = sqrt(alpha)`
or `(2pi)/(T) = sqrt(alpha) :. T = (2pi)/(sqrt(a))`


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