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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity isA. `0.10 ms^(-1)`B. `0.15 ms^(-1)`C. `0.8 ms^(-1)`D. `0.26 ms^(-1)` |
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Answer» Correct Answer - B `v_("max")=a omega = a xx (2 pi)/(T)=(50xx10^(-3)) xx (2pi)/(2)` =`0.15 ms^(-1) ` |
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