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If a small babyof mass m is moving with angular velocity `omega` in a circle of radius r, then its K.E. will beA. `(momega r)/(2)`B. `(m omega ^(2) r )`C. `(m omega ^(2) r^(2))/(2)`D. `(m omega r ^(2))/(2)` |
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Answer» Correct Answer - C `KE=(1)/(2)mv^(2) (v=r omega)` `therefore KE=(1)/(2) mr^(2) omega ^(2) ` `=(m omega ^(2) r^(2))/(2)`. |
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