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If a source of power 4 kW produces 1020 photons per second, the radiation belongs to a part of the spectrum called : |
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Answer» `gamma`-rays or `(6.6xx10^(-34)xx3xx10^(8))/(4xx10^(3))xx10^(20)=(19.8)/(4)xx10^(-9)` `~=50Å` (X-rays) |
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