If a source of sound approaches a stationery observer with velocity v then he observes an increase in frequency equal to Deltan_(1)if source recedes away from the stationary observer with same velocity v then he observer a decrease in frequency equal to Deltan_(2)then:

If a source of sound approaches a stationery observer with velocity v

1.	If a source of sound approaches a stationery observer with velocity v then he observes an increase in frequency equal to Deltan_(1)if source recedes away from the stationary observer with same velocity v then he observer a decrease in frequency equal to Deltan_(2)then:
Answer» `Deltan_(1)=Deltan_(2)` `Deltan_(1)geDeltan_(2)` `Deltan_(1)leDeltan_(2)` `Deltan_(1)geDeltan_(2) or Deltan_(2)geDeltan_(1)`DEPENDING UPON velocity V Solution :`Deltan_(1)="f"_(0)(v)/(v-v_(s)) - f_(0)=(v_(s)f_(0))/(v-v_(s))` `Deltan_(2)=f_(0)-"f"_(0) (v)/(v+v_(s)) = (v_(s)f_(0))/(v+v_(s))` clearly `Deltan_(1)geDeltan_(2)`

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If a source of sound approaches a stationery observer with velocity v then he observes an increase in frequency equal to Deltan_(1)if source recedes away from the stationary observer with same velocity v then he observer a decrease in frequency equal to Deltan_(2)then:

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