1.

If a sphere is rolling, the ratio of the translational energy to total kinetic energy is given by

Answer»

`7:10`
`2:5`
`10:7`
`5:7`

SOLUTION :TOTAL kinetic energy
`E=_("trans")+E_("not")=1/2mv^(2)+1/2lomega^(2)`
`=1/2mv^(2)+1/2xx(2/5mr^(2))omega^(2)=1/2mv^(2)+1/5mv^(2)=7/10mv^(2)`
`THEREFORE(E_("trans"))/(E_("total"))=(1/2mv^(2))/(7/10mv^(2))=5/7`


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