If a spoke is connected between the rim of the wheel and the centre (axlc) and B_(mu) is the earth 's horizontal component of total field perpendicular to the plane of the wheel and the wheel is rotated with an angular speed, then what will be the induced emf between the ends of the spoke ?

If a spoke is connected between the rim of the wheel and the centre (a

1.	If a spoke is connected between the rim of the wheel and the centre (axlc) and B_(mu) is the earth 's horizontal component of total field perpendicular to the plane of the wheel and the wheel is rotated with an angular speed, then what will be the induced emf between the ends of the spoke ?
Answer» Solution :Induced EMF `=1/2 BomegaR_2`. Note : Induced emf .E. `=Bd/(dt)` (area of a SECTOR swept by the between the two POINTS on the rim). i.e., `e=Bd/(dt)((R_2)/2theta)=1/2BR^2(d""theta)/(dt)=1/2BR^2omega`

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If a spoke is connected between the rim of the wheel and the centre (axlc) and B_(mu) is the earth 's horizontal component of total field perpendicular to the plane of the wheel and the wheel is rotated with an angular speed, then what will be the induced emf between the ends of the spoke ?

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