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If a spring of stiffness k is cut into two parts A and B of length La and Lb = 2:3, then the stiffness of spring A is ? [AIEEE 2011] |
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Answer» g is cut into two parts of length La and Lb Also given that La:Lb=2:3 If the length of spring is L , then La = 2L/5And length of B , Lb= 3L/5We know, for spring FORCE , spring constant or stiffness of spring is INVERSELY proportional to length of spring .e.g.,Kα 1/LIf intial spring constant is K then, kL=KaLa=KbLb Then,KA= k/(2/5) = 5k/2And Kb= k/(3l/5) = 5k/3Hence, stiffness of A is given by 5k/2.HOPING THIS WILL HELP YOU PLZ MARK AS BRAINLIEST AND FOLLOW ME |
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