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If `a = sqrt3, b = (1)/(2) (sqrt6 + sqrt2), and c = sqrt2`, then find `angle A` |
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Answer» Using Cosine Rule `cos A = (b^(2) + c^(2) -a^(2))/(2bc)` `= ((1//4) (8 + 4 sqrt3) + 2 - 3)/(sqrt12 + sqrt4) = (1 + sqrt3)/(2(1 + sqrt3)) = (1)/(2)` So, `A = (pi)/(3)` |
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