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If a ston s to at a point which is at a distance d away and at a height h avove the point from where the stone starts, then what is the value of initial speed u if the stone is lauched at angle `theta`? A. `g/(cos theta) sqrt(d/(2(dtan theta-h))`B. `d/(cos theta) sqrt(d/(2(dtan theta-h))`C. `sqrt((gd^(2))/((h cos^(2) theta)))`D. `sqrt((gd^(2))/((d-h)))` |
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Answer» Correct Answer - b `h=(u sin theta)t-1/2"gt"^(2)` `d=(u cos theta)t` `t=d/(u cos theta)` `h=u sin theta.d/(u cos theta)-1/2g.(d^(2))/(u^(2)cos^(2)theta)` `u=d/(cos theta)sqrt(g/(2(dtan theta-h)))` |
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