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If a thin uniform wire of length 1m is bent into an equilateral triangle and carries a current of sqrt3A in anticlockwise direction, find the net magnetic induction at the centroid |
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Answer» Solution :`B_("net")=3B_("each side")` `B_("net")=3(mu_(0))/(4PI)xxI/r(sin60^(@)+sin60^(@))` `(becauser=a/(2sqrt3))` `=3XX(mu_(0))/(4pi)I/r(2sin60^(@))=3xx(mu_(0))/(4pi)(I(2sqrt3))/a2xx(SQRT3)/2=18(mu_(0))/(4pi)I/a` `B=18xx10^(-7)XX(sqrt3)/(1/3)=54sqrt3xx10^(-7)T`
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