1.

If a $\triangle ABC$ ,$\angle B$ = $\frac{\pi}{3}$ ,$\angle C$ = $\frac{\pi}{4}$ ,and D divides BC internally in the ratio 1 : 3 then $\frac{sin\angle BAD}{sin\angle CAD}$ to equal to1). $\frac{1}{\sqrt{2}}$2). $\frac{1}{\sqrt{3}}$3). $\frac{1}{\sqrt{6}}$4). $\sqrt{6}$

Answer» OPTION 3 is the RIGHT ANSWER


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