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In a right-angled triangle XYZ, right-angled at Y, if XY = $2\sqrt{6}$ and XZ - YZ = 2, then sec X + tan X is1). $\frac{1}{\sqrt{6}}$2). $\sqrt{6}$3). $2\sqrt{6}$4). $\frac{\sqrt{6}}{2}$ |
Answer» OPTION 2 : - $\SQRT{6}$ | |