If a unimolecular reaction, A(g) toProducts, takes place according to the mechanism (I) A+Aoverset(k_(1))underset(k_(-1))(hArr)A^(a)+A (II) A^(a)underset(k_(2))(to)P where k_(1), k_(-1) and k_(2) are the rate constants and P, A and A^(a) stand for product molecule, normal molecule of reactant and activated molecules of reactant and activated molecules of reactant respectively. For the reaction scheme, X+Yoverset(k_(f))underset(k_(b))(hArr)Z, Y+Zoverset(k)(to)T, the rate equation for the formation of T will be

If a unimolecular reaction, A(g) toProducts, takes place according to

1.	If a unimolecular reaction, A(g) toProducts, takes place according to the mechanism (I) A+Aoverset(k_(1))underset(k_(-1))(hArr)A^(a)+A (II) A^(a)underset(k_(2))(to)P where k_(1), k_(-1) and k_(2) are the rate constants and P, A and A^(a) stand for product molecule, normal molecule of reactant and activated molecules of reactant and activated molecules of reactant respectively. For the reaction scheme, X+Yoverset(k_(f))underset(k_(b))(hArr)Z, Y+Zoverset(k)(to)T, the rate equation for the formation of T will be
Answer» `(d(T))/(dt)=(k_(f)K[X][Y])/(k_(B)+k[Y])` `(d(T))/(dt)=(k_(f)k_(b)k[X][Y])/(k_(b)+k[B])` `(d(T))/(dt)=(k_(f)k[X][Y]^(2))/(k_(b)+k[B])` `(d(T))/(dt)=(k_(b)k[A][B])/(k_(b)k+k[B])` Answer :B