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If a voltage of 2+5j and another voltage of 3+ 6j flows through two different resistors, connected in series, in a circuit, find the total voltage in the circuit.(a) 2+5j V(b) 3+6j V(c) 5+11j V(d) 5+10j VThe question was asked by my college professor while I was bunking the class.This intriguing question comes from Representation of an Alternating Quantity by a Phasor in section Alternating Voltage and Current of Basic Electrical Engineering

Answer»

The correct answer is (c) 5+11j V

The explanation: The total voltage in the circuit is the sum of the TWO VOLTAGES where we add the REAL parts and IMAGINARY parts separately.

Therefore, Vtotal= 5+11j V.



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