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If `a^x=b, b^y=c and c^z=a` then find the value of xyz |
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Answer» `a^x = b; b^y = c ; c^z = a` `a^x = b` `log a^x = log b` `x log a = log b` `x = log b/log a = log_a b` now , `b^y = c` `log b^y = log c` `y log b = log c` `y = log_b c` `c^z = a` `log c^z = log a` `z logc = log a` `z = log_c a` now, `xyz = log_a b xx log_b c xx log_c a` `xyz = log b/ log a xx log c/ log b xx log a/log c` `xyz = 1` Answer |
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