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If `A(x)={:[(e^(x),e^(x)),(e^(-x),e^(-x))]:}` then A(x) A(y)=A. A(x+y)A(x-y)B. A(x+y)+A(x-y)C. A(x+y)-A(x-y)D. A(x+y) |
Answer» Correct Answer - B `A(x)={:[(e^(x),e^(x)),(e^(-x),e^(-x))]:}` `A(y)={:[(e^(y),e^(y)),(e^-y,e^(-y))]:}` `A(x)A(y)={:[(e^(x+y)+e^(x-y),e^(-x)e^(y)+e^(x)e^(-y)),(e^(-x)e^(y)+e^(-x)e^(-y),e^(-x)e^(y)+e^(-x)e^(-y))]:}` `{:[(e^(x+y)+e^(x-y),e^(x+y)+e^(x-y)),(e^(-x+y)+e^(-x-y),e^(-x+y)+e^(-x-y))]:}` `{:[(e^(x+y)+e^(x-y),e^(x+y)+e^(x-y)),(e^(-(x-y))+e^(-(x+y)),e^(-(x-y))+e^(-(x+y)))]:}` =A(x+y)+A(x-y). |
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