1.

If A (x, y) is equidistant from P (–3, 2) and Q (2,–3), then (a) 2x = y (b) x = – y (c) x = 2y (d) x = y

Answer»

(d) x = y

Given, AP = AQ 

⇒ AP2 = AQ2 

⇒ (x + 3)2 + (y – 2)2 = (x – 2)2 + (y + 3)2 

⇒ x2 + 6x + 9 + y2 = x2 – 4x + 4 + y2 + 6y + 9 

⇒ 10x = 10y ⇒ x = y



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