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If A (x, y) is equidistant from P (–3, 2) and Q (2,–3), then (a) 2x = y (b) x = – y (c) x = 2y (d) x = y |
Answer» (d) x = y Given, AP = AQ ⇒ AP2 = AQ2 ⇒ (x + 3)2 + (y – 2)2 = (x – 2)2 + (y + 3)2 ⇒ x2 + 6x + 9 + y2 = x2 – 4x + 4 + y2 + 6y + 9 ⇒ 10x = 10y ⇒ x = y |
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