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If A = \([(x,y):y = \frac{1}x,0≠ x∊R] \) and B [(x,y):y = - x,x ∊ R], then write A⋂B. |
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Answer» Here, A = {\((x,y):y = \frac{1}x,0≠ x∊R\)}and B = {(x,y):y = - x, xϵR A⋂B = {\((x,y):y = \frac{1}x,0≠ x∊R\)} and {(x,y):y = - x,xϵR} = {\((x,y):-x = \frac{1}x, x∊R\)} = {(x, y):-x2 =1,x ϵ R} = {(x, y):x2 =-1,x ϵ R} = ϕ (∵ there is no such that x2 = - 1) |
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