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If a²+b²=13 and ab=6, find : 1. a+b 2. a-b |
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Answer» Answer: 3(a+B) 2 −2(a−b) 2
We know, (a+b) 2 =a 2 +b 2 +2ab =13+2(6) =13+12 =25 =>(a+b)=± 25
=>(a+b)=±5 Again, (a−b) 2 =a 2 +b 2 −2ab =13−2(6) =13−12 =1 =>(a−b)=±1 Putting the VALUES, we get, 3(±5) 2 −2(±1) 2
=75−2 =73 |
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