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If accidentally the calorimeter remained open to atmosphere was for some time during the experiment, due to which the steady state temperature comes out to be 30^(@)c, then total heat lost to surrounding during the experiment, is (Use the specific heat capacity of the liquid from previous question). |
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Answer» `20 kcal` `=(1000)(1//2)(80-30)=25,000 cal` Heat absorted by the water CALORIMETER SYSTEM `=(900)(1)(40-30)+(200)(1//2)(40-30)` `=10,000 cal` So heat LOSS to surrounding `=15,000 cal` |
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