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If accidently the calorimeter remained open to atmosphere for some time during the experiment, due to which the steady state temperature comes out to be `30^(@)C`, then total heat loss to surrounding during the experiment, is (Use the specific heat capacity of the liquid from previous questions).A. `20 kcal`B. `15 kcal`C. `10 kcal`D. `8 kcal` |
Answer» Correct Answer - B Heat given by the sphere `=(1000)(1//2)(80-30) = 25000 cal` Heat absorbed by the water calomiter system `=(900)(1)(30-20)+(200)(1//2)(30-20)` `=10,000 cal` So heat loss to surrounding =`15000 cal`. |
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