1.

If AD, BE , CF are internal bisectors of the angles of Delta ABC, " then " (cos A//2)/(AD) + (cos B//2)/(BE) + (cos C//2)/(CF) =

Answer»

`(ABC)/(2s)`
`(2s)/(abc)`
`(AB + bc + CA)/(abc)`
`(a + B + c)/(abc)`

ANSWER :C


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