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If alfa,beeta are the zeroes of the Polynomial, 5√5x² + 20x+3√5, find (alpha×beeta)2 |
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Answer» SINCE, à and ß are zero GIVEN polynomial so, à.ß=c/a =3√5/5√5 =3/5 (à.ß)²=(3/5)²=9/25 |
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