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if alpha and beta are the zeros of the polynomial x² + 3x - 2 (x + 7) then the value of (alpha + 1) (beta + 1) = |
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Answer»
Given: α,β are zeroes of the polynomial 4x +3x+7 To find the value of α 1 + β 1
2 +bx+c=0 Then sum of roots = a −b and PRODUCT of roots= a c
From the given quadratic equation, α+β=− 4 3 and αβ= 4 7
Therefore, α 1 + β 1 = αβ α+β
= 4 7
− 4 3
=− 7 3
⇒ α 1 + β 1 =− 7 3
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