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If `alpha,beta`are the roots of the equation `a x^2+b x+c=0,`then find the roots of the equation `a x^2-b x(x-1)+c(x-a)^2=0`in term of `alphaa n dbetadot` |
Answer» `ax^(2) - bx (x - 1) + c (x -1)^(2) = 0` `rArr (ax)/((1-x)^(20)) + (bx)/( 1- x) + c = 0` (1) Now , `alpha` is a root of `ax^(2) +bx + c = 0 `. Then let `alpha = (x) /(1-x)` `rArr x = (alpha)/(alpha + 1)` Hence, the roots of (1) are `alpha //(1 + alpha ),beta//(1 + beta)`. |
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