If `alpha+beta+gamma =2 and veca=alphahati+betahatj+gammahatk, hatkxx (hatkxxveca)=vec0` then gamma= (A) 1 (B) -1 (C) 2 (D) none of these

If `alpha+beta+gamma =2 and veca=alphahati+betahatj+gammahatk, hatkxx

1.	If `alpha+beta+gamma =2 and veca=alphahati+betahatj+gammahatk, hatkxx (hatkxxveca)=vec0` then gamma= (A) 1 (B) -1 (C) 2 (D) none of these
Answer» Correct Answer - C Since `(alpha, beta,gamma)` lies on the plane `x+y+z=2`. `:.alpha+beta+gamma=2`……………i We have `hatkxx(hatkxxveca)=vec0` `implies(hatk.hatk)veca-(hatk.veca)hatk=vec0` `implies veca-gammahatk=vec0impliesalpha hati+betahatj=vec0impliesalpha=beta=0` Putting `alpha=beta=0` i (i) we get `gamma=2`.

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If `alpha+beta+gamma =2 and veca=alphahati+betahatj+gammahatk, hatkxx (hatkxxveca)=vec0` then gamma= (A) 1 (B) -1 (C) 2 (D) none of these

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