1.

If alpha+beta+gamma =2pi, then

Answer»

`"tan"(ALPHA)/(2)+"tan"(beta)/(2)+"tan"(GAMMA)/(2)="tan"(alpha)/(2)"tan"(beta)/(2)"tan"(gamma")/(2)`
`"tan"(alpha)/(2)"tan"(beta)/(2)+"tan"(beta)/(2)"tan"(gamma)/(2)+"tan"(gamma)/(2)"tan"(alpha)/(2)=1`
`"tan"(alpha)/(2)+"tan"(beta)/(2)+"tan"(gamma)/(2)=-"tan"(alpha)/(2)"tan"(beta)/(2)"tan"(gamma)/(2)`
`sum tan((alpha)/(2))tan((beta)/(2))=-1`

Answer :A


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