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If `alpha,beta,gamma` are the cube roots of p, then for any x,y,z `(x alpha + y beta + z gamma)/(x beta + y gamma + z alpha` = |
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Answer» Correct Answer - `omega^(2)` `(xalpha+ybeta+zgamma)/(zbeta+ygamma+zalpha)=(x(p)^(1//3)+y(p)^(1//3)+omega+z(p)^(1//3)omega^2omega^2x(+yomega+zomega^2))/(x(p)^(1//3)omega^2+y(p)^(1//3)omega^(3)+z(p)^(1//3)omegaomega^2(xomega+yomega^2+z))` `(omega^2(x+yomega+zomega^2))/(x+yomega +zomega^2)=omega` |
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