1.

If (alpha, beta) is the centroid of the triangle, whose sides are ax^(2)+2hxy+by^(2)=0 and lx+my=1, then show that (alpha)/(bl-hm)=(beta)/(am-hl)=(2)/(3(bl^(2)-2hlm+am^(2)))

Answer»


ANSWER :`(2)/(3(BL^(2)-2hlm+am^(2)))`


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