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If an A.P. consists of n terms with first term a and nth term ls how that the sum of the mth term from the beginning and the mth term from the end is (a+l). |
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Answer» Given, a = a Last term, l = l We have to prove that the sum of the mth term from the beginning and mth term from the end is (a + 1) Now, mth term from the beginning, am(b) = a + (m – 1) l = a + ml – l (i) Again mth term from the end am(e) = l – (m – 1)l = l – ml + l = 2l – ml (ii) By adding (i) and (ii), we get a + ml – l + 2l – ml = a + l Hence, proved |
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