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If an air bubbles rises from the bottom of a mercury tank to the top its volume becomes `1(1)/(2)` times. When normal pressure is `76 cm` of `Hg` then the depth of the `Hg` tank isA. `38 cm`B. `123 cm`C. `76 cm`D. `49 cm` |
Answer» Correct Answer - A `P_(1)V_(1) = P_(2)V_(2) , (H + h)V_(1) = HV_(2)` |
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