If an electron having kinetic energy 2 eV is accelerated through the p – InterviewSolution

1.	If an electron having kinetic energy 2 eV is accelerated through the potential difference of 2 volt. Then calculate the wavelength associated with the electron
Answer» Solution :Initial kinetic energy `KE=2 ev` INCREASE in `KE` due to acceleration `=qxxV=exx2v=2eV` `:.` Fimal kinetic energy, `KE_(f)=2+2=4 eV`. `:.` Associated de-Broglie WAVELENGTH, `lambda=12.27/sqrt(4)=6.15 Å`

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