InterviewSolution
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InterviewSolution
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If an electron in a hydrogen atom jumps from the `3rd` orbit to the `2nd` orbit, it emits a photon of wavelength `lambda`. When it jumps form the `4th` orbit to the `3dr` orbit, the corresponding wavelength of the photon will beA. `(16)/(25)lamda`B. `(9)/(16)lamda`C. `(20)/(7)lamda`D. `(20)/(13)lamda` |
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Answer» Correct Answer - C `(1)/(lamda)=R(1)^(2)((1)/(2^(2))-(1)/(3^(3)))` `(1)/(lamda_(2))=R(1)^(2)((1)/(3^(2))-(1)/(4^(2)))` `((1)/(lamda))/((1)/(lamda_(2)))=((1)/(4)-(1)/(9))/((1)/(9)-(1)/(16))=((5)/(4xx9))/((16-9)/(9xx16))` `(lamda_(2))/(lamda)=(5)/(4xx9)xx(9xx16)/(7)=(20)/(7)` `lamda_(2)=(20)/(7)lamda` |
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