1.

If an electron in any hydrogen atom jumps from an orbit n_(i)=3 to an orbit with level n_f= 2, the frequency of the emitted radiation is :

Answer»

`v=(36c)/(5R)`
`v=(cR)/(6)`
`v=(5Rc)/(36)`
`v=(6C)/(R)`

Solution :`1/LAMBDA=R (1/n_(1)^2-1/n_(f)^(2))`
`c=v lambda, 1/lambda=v/c`
`v/c=R (1/n_(i)^(2)-1/n_(f)^(2))`
`v=cR (1/2^(2)-1/3^(2))=5/(36)cR`


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