If an electron in hydrogen atom jumps from an orbit of level n= 3 to an orbit of level n =2, the emitted radiation has a frequency (R= Rydberg constant, c= velocity of light) :

If an electron in hydrogen atom jumps from an orbit of level n= 3 to a

1.	If an electron in hydrogen atom jumps from an orbit of level n= 3 to an orbit of level n =2, the emitted radiation has a frequency (R= Rydberg constant, c= velocity of light) :
Answer» `(RC)/(25)` `(5Rc)/(36)` `(3Rc)/(27)` `(8Rc)/(9)` Solution :`1/lambda=R_(H) (1/n_(F)^(2)-1/n_(i)^(2))` `c/lambda=Rc (1/n_(f)^(2)-1/n_(i)^(2))` `v=Rc (1/2^(2)-1/3^(2))` `=Rc (1/4-1/9)` `v=5/(36)Rc`.

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If an electron in hydrogen atom jumps from an orbit of level n= 3 to an orbit of level n =2, the emitted radiation has a frequency (R= Rydberg constant, c= velocity of light) :

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