If an electron in `n = 3` orbit of hydrogen atom jumps down to `n = 2` orbit, the amount of energy reeased and the and the wavelength of radiation emitted areA. `0.85 eV, 6566 Å`B. `0.89 eV, 1240 Å`C. `1.89 eV, 6566 Å`D. `1.5 eV, 6566 Å`

If an electron in `n = 3` orbit of hydrogen atom jumps down to `n = 2`

1.	If an electron in `n = 3` orbit of hydrogen atom jumps down to `n = 2` orbit, the amount of energy reeased and the and the wavelength of radiation emitted areA. `0.85 eV, 6566 Å`B. `0.89 eV, 1240 Å`C. `1.89 eV, 6566 Å`D. `1.5 eV, 6566 Å`
Answer» Correct Answer - C `(1)/(lambda) = R[(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` `(1)/(lambda) = R ((1)/(2^(2)) - (1)/(3^(2)))` implies `lambda = (36)/(5 R) = (36 xx 10^(-7))/(5 xx 1.097) = 6.566 xx 10^(-7)` `lambda = 6566 Å` `E = (h c)/(lambda) = (6.64 xx 10^(-34) xx 3 xx 10^(8))/(6.566 xx 10^(-7)) = 3.05 xx 10^(-19) J` `:. E = 1.89 e V`

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If an electron in `n = 3` orbit of hydrogen atom jumps down to `n = 2` orbit, the amount of energy reeased and the and the wavelength of radiation emitted areA. `0.85 eV, 6566 Å`B. `0.89 eV, 1240 Å`C. `1.89 eV, 6566 Å`D. `1.5 eV, 6566 Å`

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