1.

If an electron moving with a speed of 2.5xx10^(7)ms^(-1) is deflected by an electric field of 1.6k(V)m^(-1) perpendicular to its circular path, then (e)/(m) for the electron will be (given radius of circular path =2.3m):

Answer»

`1.67xx10^(11)Ckg^(-1)`
`1.76xx10^(11)Ckg^(-1)`
`1.7XX10^(11)Ckg^(-1)`
`1.59xx10^(11)Ckg^(-1)`

SOLUTION :`EE=(mv^(2))/(r)`
`:.(e)/(m)=(v^(2))/(Er)=1*7xx10^(11)C Kg^(-1)`


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