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If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solutionis Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-) In basic solution is : ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-). The standard potentials for two nonadjacent species can also be calculated by using the concept that DeltaG^(@) is an additive property but using potential is not an assitive property and DeltaG^(@)=-nFx^(0), If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of DeltaG^(@)//F against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The moststable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. Which of the following statement is correct accordingto abovequestion ? |
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Answer» `A^(+1)` undergoes disproportionation into A and `A^(2+)` |
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