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If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host?(a) 172.16.112.0(b) 172.16.0.0(c) 172.16.96.0(d) 172.16.255.0The question was asked in examination.Question is from Designing Subnet Masks in chapter TCP/IP Protocol Suite of Computer Network

Answer»

Correct option is (a) 172.16.112.0

For explanation I would SAY: A /25 mask is 255.255.255.128. Used with a Class B NETWORK, the third and fourth octets are used for subnetting with a total of 9 subnet BITS, 8 bits in the third OCTET and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on-which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subne



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