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If an open organ pipe is sounded with a tuning fork having frequency 256 Hz resonance occurred at 35 cm and 105 cm the velocity of sound is : |
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Answer» 360 m/s `therefore (lambda)/(2) = l_(2) - l_(1 ) "" rArr lambda_(2) = 2 (105 -35) ` = 140 cm=1.4 m V - v `lambda= 256 X 1.4 = 358. 4` m/s . Hence the correct choice is (a) . |
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