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If & and B are the zeroes of the quad polynomial f(x) = x²- p(x +1)-&, show that(a +1) ( beta + 1 ) = 1-c​

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ᴏɴ↓:-If & and B are the zeroes of thequad polynomial f(x) = x²- p(x +1)-&,show that(a +1) ( beta + 1 ) = 1-c•Gɪᴠᴇɴ:-& and B are the zeroes of thequad polynomial f(x) = x²- p(x +1)-&•Sʜᴏᴡ ᴛʜᴀᴛ:-(a +1) ( beta + 1 ) = 1-c•Sᴏʟᴜᴛɪᴏɴ:-If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1)ASKED by Nimmi | 7TH May, 2019, 11:36: PMExpert Answer:If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1) x2 - p(x + 1) - c = x2 - px - p - c COMPARING with AX2 + bx + c, we get a= 1 , b = -p and c = - p - c α and β are the zeroes of the given polynomial. → α + β = -b/a = -(-p)/1 = pand αβ = c/a = -p - c / 1 = -p - c To find: (α + 1)(β + 1) (α + 1)(β + 1) = αβ + α + β + 1 = - p - c + p + 1 = 1 - c



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