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If angles A, B, C of a ΔABC form an increasing AP, then sin B =(a) 1/2(b) √3/2(c) 1(d) 1/√2 |
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Answer» (b) In ΔABC, angles A,B,C are in A.P., B – A = C – B 2B = A + C ...(i) also, A + B + C = 180° (Angle sum Property) 2 B + B = 180° B = 60° Hence, sin B = sin60° = √3/2 |
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