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If angular momentum is conserved in a system whose moment of inertia is decreased, will its rotational kinetic energy be also conserved ? Explain. |
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Answer» Here, `L = I omega =` constant `K.E.` of rotation, `K = (1)/(2) I omega^(2)` `K = (1)/(2I)I^(2) omega^(2) = (L^(2))/(2I)` As `L` is constant, `:. K prop 1//l` When moment of inertia `(I)` decrease, `K.E.` of rotation `(K)` increase. Thus `K.E.` of rotation is not conserved. |
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